area of ∆APQarea of ∆PBQ = 12 × AP × QN12 × PB × QN = APPB
Similarly, area of ∆APQarea of ∆QCP = 12 × AQ × PM12 × QC × PM = AQQC  ………..(2)
According to the property of triangles, the triangles drawn between the same parallel lines and on the same base have equal areas.