Function of an integer raised in a power

SUBMITTED BY: davindran21

DATE: Oct. 12, 2016, 1:51 a.m.

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  1. /***********************************************************
  2. * Function of an integer raised in a power
  3. * and the calculation of the sum of a series of integers (1^e+2^e....+n^e) raised in a power.
  4. *
  5. * Author: Spyridon Arvanitis
  6. * Date : Jan, 2014
  7. ***********************************************************/
  9. #include <stdio.h>
  11. int power(int b, int e);
  13. int main()
  15. {
  17. /* n= positive integer e= power, S= sum of integers raised in e power*/
  19. int e,n,i,S=0;
  21. /*Input e and n. Control that the inputs are positive numbers*/
  23. printf (\\"Enter the last number (n) of the series\n\\");
  25. scanf (\\"%d\\", &n);
  27. if (n<=0) /* if n is a negative number*/
  29. {
  31. printf (\\"Error. You gave a negative number. Program ends.\n\\");
  33. return 0;
  35. }
  37. printf (\\"Input the number to be the power\n\\");
  39. scanf (\\"%d\\", &e);
  41. if (e<=0) /* if n is a negative number*/
  43. {
  45. printf (\\"Error. You gave a negative number. Program ends.\n\\");
  47. return 0;
  49. }
  51. /* Calling function power n times*/
  53. for (i=1; i<=n; i++)
  55. {
  57. S += power (i,e);
  58. }
  60. printf (\\"The sum of the 1-%d series of integers raised in %d is %d\\", n,e, S);
  62. return 0;
  64. }
  66. /*Fuction to calculate a number raised in power*/
  68. int power(int b, int e)
  70. {
  72. int power=1;
  74. int i;
  76. if (b<=0)
  78. {
  79. return -1;
  80. }
  82. if (e<=0)
  84. {
  85. return -1;
  86. }
  88. for (i=1; i<=e;i++)
  90. {
  92. power*=b;
  94. }
  96. return (power);
  98. }
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