c++, how to store ARGB in 1 int.

SUBMITTED BY: Guest

DATE: Nov. 21, 2013, 2:58 p.m.

FORMAT: C++

SIZE: 521 Bytes

Raw Download

HITS: 987

Report

#include <iostream>

using namespace std;

int main(){
	
	//Creating in with argb values from 0 to 255
	int argb =  (255&0xff) +  //ALPHA
				((200&0xff)<<8) + 	//RED
				((150&0xff)<<16) + 	//GREEN
				((100&0xff)<<24);	//BLUE
			
	cout << "ALPHA = " << (argb&0xff) << endl;
	cout << "RED = " << ((argb>>8)&0xff) << endl;
	cout << "GREEN = " << ((argb>>16)&0xff) << endl;
	cout << "BLUE = " << ((argb>>24)&0xff) << endl;
	
	cin.get();
				
	return 0;
}