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SUBMITTED BY:
manisri69
DATE:
Aug. 12, 2016, 2:19 p.m.
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area of ∆APQarea of ∆PBQ = 12 × AP × QN12 × PB × QN = APPB
Similarly, area of ∆APQarea of ∆QCP = 12 × AQ × PM12 × QC × PM = AQQC ………..(2)
According to the property of triangles, the triangles drawn between the same parallel lines and on the same base have equal areas.
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