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SUBMITTED BY:
SOLLYM
DATE:
March 23, 2016, 3:35 p.m.
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sinax cosbx = 1/2 [sin(a-b)x + sin(a+b)x]
cosax cosbx = 1/2 [cos(a-b)x + cos(a+b)x]
sinax sinbx = 1/2 [cos(a-b)x - cos(a+b)x]
sin2x = 1/2 [1 – cos(2x)]
cos2x = 1/2 [1 + cos(2x)]
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